Question

The shape of $[Cu(N{H}_3{)}_4]C{l}_2$ is:

• A. Tetrahedral
• B. Octahedral
• C. Square planar
• D. Pyramidal

Answer 1

Answer: (C)

$N{H}_3$ has more field strength. So it forms low spin complexes. Due to presence of one unpaired electron it is paramagnetic.
$4\left(N{H}_3\right)$ molecules has 8 electrons. So, they require 4 sub orbitals - 1d, $1s,2p$. So, its hybridization becomes $ds{p}^2$. Its co-ordination number $=4$
Co-ordination number and hybridization decides the shape with 4 coordination number and dsp hybridization, it has a square planar structure.