The shaded region in the figure is the solution set of the inequations.

Question

The shaded region in the figure is the solution set of the inequations. (A) 4x + 5y le 20, 3x + 10y le 30, x le 6, x, y ge 0 (B) 4x + 5y ge 20, 3x + 10y le 30, x le 6, x, y ge 0 (C) 4x + 5y le 20, 3x + 10y le 30, x ge 6, x, y ge 0 (D) 4x + 5y ge 20, 3x + 10y le 30, x ge 6, x, y ge 0

Tardigrade Admin · Accepted Answer

Correct answer is (b) 4x + 5y ge 20, 3x + 10y le 30, x le 6, x, y ge 0

Q. The shaded region in the figure is the solution set of the inequations.

$4 x + 5 y \leq 20, 3 x + 10 y \leq 30, x \leq 6, x, y \geq 0$

$4 x + 5 y \geq 20, 3 x + 10 y \leq 30, x \leq 6, x, y \geq 0$

$4 x + 5 y \leq 20, 3 x + 10 y \leq 30, x \geq 6, x, y \geq 0$

$4 x + 5 y \geq 20, 3 x + 10 y \leq 30, x \geq 6, x, y \geq 0$

Correct answer is (b) $4 x + 5 y \geq 20, 3 x + 10 y \leq 30, x \leq 6, x, y \geq 0$

Q. The shaded region in the figure is the solution set of the inequations.

4x+5y≤20,3x+10y≤30,x≤6,x,y≥0

4x+5y≥20,3x+10y≤30,x≤6,x,y≥0

4x+5y≤20,3x+10y≤30,x≥6,x,y≥0

4x+5y≥20,3x+10y≤30,x≥6,x,y≥0

Correct answer is (b) 4x+5y≥20,3x+10y≤30,x≤6,x,y≥0

$4 x + 5 y \leq 20, 3 x + 10 y \leq 30, x \leq 6, x, y \geq 0$

$4 x + 5 y \geq 20, 3 x + 10 y \leq 30, x \leq 6, x, y \geq 0$

$4 x + 5 y \leq 20, 3 x + 10 y \leq 30, x \geq 6, x, y \geq 0$

$4 x + 5 y \geq 20, 3 x + 10 y \leq 30, x \geq 6, x, y \geq 0$

Correct answer is (b) $4 x + 5 y \geq 20, 3 x + 10 y \leq 30, x \leq 6, x, y \geq 0$