Q.
The set of values of x satisfying simultaneously the inequalities log0.3(710(log25−1))(x−8)(2−x)≥0 and 2x−3−31>0 is
337
105
Continuity and Differentiability
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Solution:
Note that Dr<0, hence given inequality (1) is true only if Nr≥0
i.e. (x−8)(x−2)<0 and 2x−3>31
i.e. 2≤x≤8 and 2x−3≥31
only x=8 satisfies both the inequality