The set of quantum numbers for the outermost electron for copper in its ground state is

Question

The set of quantum numbers for the outermost electron for copper in its ground state is  (A) 3 , 2 , 2 , + 1/2 (B) 4 , 1 , 1 , + 1/2 (C) 4 , 2 , 2 , +1/2 (D) 4 , 0 , 0 , +1/2

Tardigrade Admin · Accepted Answer

The electronic configuration of the Cu atom is 29 Cu =[ Ar ] 3 d10 4 s1 Since, the outermost shell is 4 s, thus outermost electron is in it. For 4 s1, n=4, l=0, m=0, s=+(1/2)

Q. The set of quantum numbers for the outermost electron for copper in its ground state is ___________

$3, 2, 2, + 1/2$

$4, 1, 1, + 1/2$

$4, 2, 2, + 1/2$

$4, 0, 0, + 1/2$

The electronic configuration of the Cu atom is

$_{29} C u = [A r] 3 d^{10} 4 s^{1}$

Since, the outermost shell is $4 s$ , thus outermost electron is in it. For $4 s^{1}$ ,

$n = 4,$

$l = 0,$

$m = 0,$

$s = + \frac{1}{2}$

Q. The set of quantum numbers for the outermost electron for copper in its ground state is ___________

3,2,2,+1/2

4,1,1,+1/2

4,2,2,+1/2

4,0,0,+1/2

The electronic configuration of the Cu atom is 29​Cu=[Ar]3d104s1 Since, the outermost shell is 4s, thus outermost electron is in it. For 4s1, n=4, l=0, m=0, s=+21​

$3, 2, 2, + 1/2$

$4, 1, 1, + 1/2$

$4, 2, 2, + 1/2$

$4, 0, 0, + 1/2$

The electronic configuration of the Cu atom is

$_{29} C u = [A r] 3 d^{10} 4 s^{1}$

Since, the outermost shell is $4 s$ , thus outermost electron is in it. For $4 s^{1}$ ,

$n = 4,$

$l = 0,$

$m = 0,$

$s = + \frac{1}{2}$