Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The set of all values of a for which displaystyle lim x arrow a([x-5]-[2 x+2])=0, where [ propto] denotes the greatest integer less than or equal to propto is equal to
Q. The set of all values of
a
for which
x
→
a
lim
([
x
−
5
]
−
[
2
x
+
2
])
=
0
, where
[
∝
]
denotes the greatest integer less than or equal to
∝
is equal to
1830
147
JEE Main
JEE Main 2023
Limits and Derivatives
Report Error
A
[
−
7.5
,
−
6.5
)
50%
B
(
−
7.5
,
−
6.5
)
50%
C
(
−
7.5
,
−
6.5
]
0%
D
[
−
7.5
,
−
6.5
]
0%
Solution:
x
→
a
lim
([
x
−
5
]
−
[
2
x
+
2
])
=
0
x
→
a
lim
([
x
]
−
5
−
[
2
x
]
−
2
)
=
0
x
→
a
lim
([
x
]
−
[
2
x
])
=
7
[
a
]
−
[
2
a
]
=
7
a
∈
I
,
a
=
−
7
a
∈
/
I
,
a
=
I
+
f
Now,
[
a
]
−
[
2
a
]
=
7
−
I
−
[
2
f
]
=
7
Case-I:
f
∈
(
0
,
2
1
)
2
f
∈
(
0
,
1
)
−
I
=
7
I
=
−
7
⇒
a
∈
(
−
7
,
−
6.5
)
Case-II:
f
∈
(
2
1
,
1
)
2
f
∈
(
1
,
2
)
−
I
−
1
=
7
I
=
−
8
⇒
a
∈
(
−
7.5
,
−
7
)
Hence,
a
∈
(
−
7.5
,
−
6.5
)