The separation of two coloured substances was done by paper chromatography. The distances travelled by solvent front, substance A and substance B from the base line are 3.25 cm .2 .08 cm and 1.05 cm. respectively. The ratio of Rf values of A to B is

Question

The separation of two coloured substances was done by paper chromatography. The distances travelled by solvent front, substance A and substance B from the base line are 3.25 cm .2 .08 cm and 1.05 cm. respectively. The ratio of Rf values of A to B is  (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

( R F A / R F B )=((2.08/3.25)/(1.05)3.25)=(2.08/1.05) ≃ 2

Q. The separation of two coloured substances was done by paper chromatography. The distances travelled by solvent front, substance $A$ and substance $B$ from the base line are $3.25 c m .2.08 c m$ and $1.05 c m$ . respectively. The ratio of $R_{f}$ values of $A$ to $B$ is ________

$\frac{R _{F_{A}}}{R _{F_{B}}} = \frac{\frac{2.08}{3.25}}{\frac{1.05}{3.25}} = \frac{2.08}{1.05} ≃ 2$

Q. The separation of two coloured substances was done by paper chromatography. The distances travelled by solvent front, substance A and substance B from the base line are 3.25cm.2.08cm and 1.05cm. respectively. The ratio of Rf​ values of A to B is ________

RFB​​RFA​​​=3.251.05​3.252.08​​=1.052.08​≃2

Q. The separation of two coloured substances was done by paper chromatography. The distances travelled by solvent front, substance $A$ and substance $B$ from the base line are $3.25 c m .2.08 c m$ and $1.05 c m$ . respectively. The ratio of $R_{f}$ values of $A$ to $B$ is ________

$\frac{R _{F_{A}}}{R _{F_{B}}} = \frac{\frac{2.08}{3.25}}{\frac{1.05}{3.25}} = \frac{2.08}{1.05} ≃ 2$