The self inductance of a solenoid that has a cross-sectional area of 1 cm 2, a length of 0.10 m and 1000 turns of wire is

Question

The self inductance of a solenoid that has a cross-sectional area of 1 cm 2, a length of 0.10 m and 1000 turns of wire is (A) 0.86 mH (B) 1.06 mH (C) 1.26 mH (D) 1.46 mH

Tardigrade Admin · Accepted Answer

L =(μ0 N2 A/l)=((4 π × 10-7 ( H / m ))(1000)2(10-4 m 2)/(0.10 m )) =1.26 × 10-3 H =1.26 mH

Q. The self inductance of a solenoid that has a cross-sectional area of $1 c m^{2}$ , a length of 0.10 m and 1000 turns of wire is

0.86 mH

1.06 mH

1.26 mH

1.46 mH

$L = \frac{μ _{0} N ^{2} A}{l} = \frac{( 4 π \times 1 0 ^{- 7} \frac{H}{m} ) ( 1000 ) ^{2} ( 1 0 ^{- 4} m ^{2} )}{( 0.10 m )}$
$= 1.26 \times 1 0^{- 3} H = 1.26 m H$

Q. The self inductance of a solenoid that has a cross-sectional area of 1cm2, a length of 0.10 m and 1000 turns of wire is