The self inductance of a coil is L, keeping the length and area same, the number of turns in the coil is increased to four times. The self inductance of coil will:

Question

The self inductance of a coil is L, keeping the length and area same, the number of turns in the coil is increased to four times. The self inductance of coil will: (A) 1 / 4 L (B) L (C) 4 L (D) 16 L

Tardigrade Admin · Accepted Answer

By the relation, L=(μ0 N2 A/1) ∴ L propto N 2 L 2=((4 N / N ))2 L ⇒ L 2=16 L

Q. The self inductance of a coil is $L$ , keeping the length and area same, the number of turns in the coil is increased to four times. The self inductance of coil will:

$1/4 L$

$L$

$4 L$

$16 L$

By the relation,
$L = \frac{μ _{0} N ^{2} A}{1}$
$∴ L \propto N^{2}$
$L_{2} = (\frac{4 N}{N})^{2} L$
$\Rightarrow L_{2} = 16 L$

Q. The self inductance of a coil is L, keeping the length and area same, the number of turns in the coil is increased to four times. The self inductance of coil will:

1/4L

L

4L

16L

By the relation, L=1μ0​N2A​ ∴L∝N2 L2​=(N4N​)2L ⇒L2​=16L

Q. The self inductance of a coil is $L$ , keeping the length and area same, the number of turns in the coil is increased to four times. The self inductance of coil will:

$1/4 L$

$L$

$4 L$

$16 L$

By the relation,
$L = \frac{μ _{0} N ^{2} A}{1}$
$∴ L \propto N^{2}$
$L_{2} = (\frac{4 N}{N})^{2} L$
$\Rightarrow L_{2} = 16 L$