The self-induced e.m.f. in a 0.1 H coil when the current in it is changing at the rate of 200 A / s is

Question

The self-induced e.m.f. in a 0.1 H coil when the current in it is changing at the rate of 200 A / s is (A) 8 × 10-4 V (B) 8 × 10-5 V (C) 20 V (D) 125 V

Tardigrade Admin · Accepted Answer

|e|=L (d i/d t) ⇒ |e|=0.1 × 200=20 V

Q. The self-induced e.m.f. in a $0.1 H$ coil when the current in it is changing at the rate of $200 A / s$ is

$8 \times 1 0^{- 4} V$

$8 \times 1 0^{- 5} V$

$20 V$

$125 V$

$∣ e ∣ = L \frac{d i}{d t} \Rightarrow ∣ e ∣ = 0.1 \times 200 = 20 V$

Q. The self-induced e.m.f. in a 0.1H coil when the current in it is changing at the rate of 200A/s is

8×10−4V

8×10−5V

20V

125V

∣e∣=Ldtdi​⇒∣e∣=0.1×200=20V

Q. The self-induced e.m.f. in a $0.1 H$ coil when the current in it is changing at the rate of $200 A / s$ is

$8 \times 1 0^{- 4} V$

$8 \times 1 0^{- 5} V$

$20 V$

$125 V$

$∣ e ∣ = L \frac{d i}{d t} \Rightarrow ∣ e ∣ = 0.1 \times 200 = 20 V$