The Schrodinger wave equation for hydrogen atom is Ψ2 s =(1/4 √2 π)((1/a0))32(2-(r/a0)) e-r a0 where a 0 is Bohr's radius. If the radial node in 2 s be at r0, then r0 would be equal to

Question

The Schrodinger wave equation for hydrogen atom is Ψ2 s =(1/4 √2 π)((1/a0))32(2-(r/a0)) e-r a0 where a 0 is Bohr's radius. If the radial node in 2 s be at r0, then r0 would be equal to (A) (a0/2) (B) 2 a0 (C) √2 a0 (D) (a0/√2)

Tardigrade Admin · Accepted Answer

2-( r / a 0)=0 at radial node r=2 a0

Q. The Schrodinger wave equation for hydrogen atom is
$Ψ_{2 s} = \frac{1}{4 2 π} (\frac{1}{a _{0}})^{32} (2 - \frac{r}{a _{0}}) e^{- r a_{0}}$
where $a_{0}$ is Bohr's radius. If the radial node in $2 s$ be at $r_{0}$ , then $r_{0}$ would be equal to

$\frac{a _{0}}{2}$

$2 a_{0}$

$2 a_{0}$

$\frac{a _{0}}{2}$

$2 - \frac{r}{a _{0}} = 0$
at radial node
$r = 2 a_{0}$

Q. The Schrodinger wave equation for hydrogen atom is Ψ2s​=42π​1​(a0​1​)32(2−a0​r​)e−ra0​ where a0​ is Bohr's radius. If the radial node in 2s be at r0​, then r0​ would be equal to

2a0​​

2a0​

2​a0​

2​a0​​

2−a0​r​=0 at radial node r=2a0​

Q. The Schrodinger wave equation for hydrogen atom is
$Ψ_{2 s} = \frac{1}{4 2 π} (\frac{1}{a _{0}})^{32} (2 - \frac{r}{a _{0}}) e^{- r a_{0}}$
where $a_{0}$ is Bohr's radius. If the radial node in $2 s$ be at $r_{0}$ , then $r_{0}$ would be equal to

$\frac{a _{0}}{2}$

$2 a_{0}$

$2 a_{0}$

$\frac{a _{0}}{2}$

$2 - \frac{r}{a _{0}} = 0$
at radial node
$r = 2 a_{0}$