The S.I. unit of length is "meter". Suppose we adopt a new unit of length which equals x meter. Then, the area of 1 m 2 expressed in terms of new unit has a magnitude

Question

The S.I. unit of length is "meter". Suppose we adopt a new unit of length which equals x meter. Then, the area of 1 m 2 expressed in terms of new unit has a magnitude (A) x (B) x2 (C) (1/x) (D) (1/x2)

Tardigrade Admin · Accepted Answer

SI unit of length = metre (m) New unit of length =x metre Hence, 1 m=(1/x) new units ∴ Area, 1 m2=1 m × 1 m =(1/x) × (1/x)=(1/x2) (in new units)

Q. The $S . I$ . unit of length is "meter". Suppose we adopt a new unit of length which equals $x$ meter. Then, the area of $1 m^{2}$ expressed in terms of new unit has a magnitude__________

$x$

$x^{2}$

$\frac{1}{x}$

$\frac{1}{x ^{2}}$

$S I$ unit of length $=$ metre $(m)$
New unit of length $= x$ metre
Hence, $1 m = \frac{1}{x}$ new units
$∴$ Area, $1 m^{2} = 1 m \times 1 m$
$= \frac{1}{x} \times \frac{1}{x} = \frac{1}{x ^{2}}$ (in new units)

Q. The S.I. unit of length is "meter". Suppose we adopt a new unit of length which equals x meter. Then, the area of 1m2 expressed in terms of new unit has a magnitude__________

x

x2

x1​

x21​

SI unit of length = metre (m) New unit of length =x metre Hence, 1m=x1​ new units ∴ Area, 1m2=1m×1m =x1​×x1​=x21​ (in new units)

Q. The $S . I$ . unit of length is "meter". Suppose we adopt a new unit of length which equals $x$ meter. Then, the area of $1 m^{2}$ expressed in terms of new unit has a magnitude__________

$x$

$x^{2}$

$\frac{1}{x}$

$\frac{1}{x ^{2}}$

$S I$ unit of length $=$ metre $(m)$
New unit of length $= x$ metre
Hence, $1 m = \frac{1}{x}$ new units
$∴$ Area, $1 m^{2} = 1 m \times 1 m$
$= \frac{1}{x} \times \frac{1}{x} = \frac{1}{x ^{2}}$ (in new units)