Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The roots of x+ log 10 x=3.375 is approximately:
Q. The roots of
x
+
lo
g
10
x
=
3.375
is approximately:
1825
208
Jharkhand CECE
Jharkhand CECE 2003
Report Error
A
2.09
B
2.909
C
2.990
D
3.003
Solution:
Roots of
x
+
lo
g
10
x
=
3.375
is approximately
2.909