Question

The roots of the equation
$2^{2x}-10.2^x+16=0$ are

• A. $2,8$
• B. $1,3$
• C. $1,8$
• D. $2,3$

Answer 1

Answer: (B)

$2^{2x}-10.2^x+16=0$
$\Rightarrow$ $(2^x-8)(2^x-2)=0$
$\Rightarrow 2^x=8,2^x=2$
$\Rightarrow 2^x=2^3,2^x=2^1$
$\Rightarrow x=3,x=1$