The rms value of potential difference v shown in the figure is

Question

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/34bf674a97ad3b488c196a953acea4d5-.png" /> The rms value of potential difference v shown in the figure is (A) (v0/2) (B) v0 (C) (v0/√3) (D) (v0/√2)

Tardigrade Admin · Accepted Answer

Vr m s2 × T=V02 × (T/2)+0 Vr m s2=(V02/2) Vr m s=(V0/√2)

Q.
The rms value of potential difference $v$ shown in the figure is

$\frac{v _{0}}{2}$

$v_{0}$

$\frac{v _{0}}{3}$

$\frac{v _{0}}{2}$

$V_{r m s}^{2} \times T = V_{0}^{2} \times \frac{T}{2} + 0$
$V_{r m s}^{2} = \frac{V _{0}^{2}}{2}$
$V_{r m s} = \frac{V _{0}}{2}$

Q. The rms value of potential difference v shown in the figure is

2v0​​

v0​

3​v0​​

2​v0​​

Vrms2​×T=V02​×2T​+0 Vrms2​=2V02​​ Vrms​=2​V0​​

Q.
The rms value of potential difference $v$ shown in the figure is

$\frac{v _{0}}{2}$

$v_{0}$

$\frac{v _{0}}{3}$

$\frac{v _{0}}{2}$

$V_{r m s}^{2} \times T = V_{0}^{2} \times \frac{T}{2} + 0$
$V_{r m s}^{2} = \frac{V _{0}^{2}}{2}$
$V_{r m s} = \frac{V _{0}}{2}$