The rms value of conduction current in a parallel plate capacitor is 6.9 μ A. The capacity of this capacitor, if it is connected to 230 V ac supply with an angular frequency of 600 rad / s, will be :

Question

The rms value of conduction current in a parallel plate capacitor is 6.9 μ A. The capacity of this capacitor, if it is connected to 230 V ac supply with an angular frequency of 600 rad / s, will be : (A) 5 pF (B) 50 pF (C) 100 pF (D) 200 pF

Tardigrade Admin · Accepted Answer

Current in capacitor I =( V / X C ) I =( V ) ×(ω C ) C =( I / V ω)=(6.9 × 10-6/230 × 600)=50 pF

Q. The rms value of conduction current in a parallel plate capacitor is $6.9 μ A$ . The capacity of this capacitor, if it is connected to $230 V$ ac supply with an angular frequency of $600 r a d / s$ , will be :

$5 pF$

$50 pF$

$100 pF$

$200 pF$

Current in capacitor $I = \frac{V}{X _{C}}$
$I = (V) \times (ω C)$
$C = \frac{I}{Vω} = \frac{6.9 \times 1 0 ^{- 6}}{230 \times 600} = 50 pF$

Q. The rms value of conduction current in a parallel plate capacitor is 6.9μA. The capacity of this capacitor, if it is connected to 230V ac supply with an angular frequency of 600rad/s, will be :

5pF

50pF

100pF

200pF