The rms speed of the molecules of a gas in a vessel is 400 text ms-1 . If half of the gas leaks out, at constant temperature, the rms speed of the remaining molecules will be:

Question

The rms speed of the molecules of a gas in a vessel is 400 text ms-1 . If half of the gas leaks out, at constant temperature, the rms speed of the remaining molecules will be: (A)  800 ms-1  (B)  400√2 ms-1  (C)  400 ms-1  (D)  200 ms-1

Tardigrade Admin · Accepted Answer

vrms propto √T Hence, rms speed remains 400 text ms-1 .

Q. The rms speed of the molecules of a gas in a vessel is $400 m s^{- 1}$ . If half of the gas leaks out, at constant temperature, the rms speed of the remaining molecules will be:

$800 m s^{- 1}$

$4002 m s^{- 1}$

$400 m s^{- 1}$

$200 m s^{- 1}$

$2002 m s^{- 1}$

$v_{r m s} \propto T$ Hence, rms speed remains $400 m s^{- 1}$ .

Q. The rms speed of the molecules of a gas in a vessel is 400ms−1 . If half of the gas leaks out, at constant temperature, the rms speed of the remaining molecules will be:

800ms−1

4002​ms−1

400ms−1

200ms−1

2002​ms−1

vrms​∝T​ Hence, rms speed remains 400ms−1 .