The reversible reaction [Cu(NH3)4]2 ++S(O3)2 -leftharpoons [Cu(NH3)3SO3]+NH3 is at equilibrium. What would not happen if ammonia is added -

Question

The reversible reaction [Cu(NH3)4]2 ++S(O3)2 -leftharpoons [Cu(NH3)3SO3]+NH3 is at equilibrium. What would not happen if ammonia is added - (A) [S O32 -] would increase (B) [C u (N H3)3 S O3] would increase (C) The value of equilibrium constant would not change (D) [C u (N H3)4]2 + would increase

Tardigrade Admin · Accepted Answer

NH3 is presenting on product side. Hence on adding NH3 , equilibrium shift to backward thus concentration of [C u (N H3)3 S O3] would decrease.

Q. The reversible reaction

$[C u (N H_{3})_{4}]^{2 +} + S (O_{3})^{2 -} ⇌ [C u (N H_{3})_{3} S O_{3}] + N H_{3}$

is at equilibrium. What would not happen if ammonia is added -

$[S O_{3}^{2 -}]$ would increase

$[C u (N H_{3})_{3} S O_{3}]$ would increase

The value of equilibrium constant would not change

$[C u (N H_{3})_{4}]^{2 +}$ would increase

$N H_{3}$ is presenting on product side. Hence on adding $N H_{3}$ , equilibrium shift to backward thus concentration of $[C u (N H_{3})_{3} S O_{3}]$ would decrease.

Q. The reversible reaction [Cu(NH3​)4​]2++S(O3​)2−⇌[Cu(NH3​)3​SO3​]+NH3​ is at equilibrium. What would not happen if ammonia is added -

[SO32−​] would increase

[Cu(NH3​)3​SO3​] would increase