Question

The resulting $a$ - $t$ graph for the given $v$ - $t$ graph is correctly represented in

• A.
• B.
• C.
• D.

Answer 1

Answer: (A)

Average acceleration for different time intervals is the slope of $v-t$ graph, which is as follows
For $0s-10s,\bar{a}=\frac{(24-0)m{s}^{-1}}{(10-0)s}=2.4m{s}^{-2}$
For $10s-18s,\bar{a}=\frac{(24-24)m{s}^{-1}}{(18-10)s}=0m{s}^{-2}$
For $18s-20s,\bar{a}=\frac{(0-24)m{s}^{-1}}{(20-18)s}=-12m{s}^{-2}$
So, the corresponding $a-t$ graph for the given $v$ - $t$ graph is as follows

This is shown correctly in graph.