The resultant capacitance of n condenser of capacitances C 1, C 2 ldots C n connected in series is given by

Question

The resultant capacitance of n condenser of capacitances C 1, C 2 ldots C n connected in series is given by (A) C s =(1/ C 1)+(1/ C 2)+ ldots ldots . .+(1/ C n ) (B) (1/ C s )=(1/ C 1)+ ldots ldots . .+(1/ C n ) (C) C s = C 1+ C 2+ ldots . .+ C n (D) C s = C 1- C 2+ ldots . .- C n

Tardigrade Admin · Accepted Answer

Correct answer is (b) (1/ C s )=(1/ C 1)+ ldots ldots . .+(1/ C n )

Q. The resultant capacitance of $n$ condenser of capacitances $C_{1}, C_{2} \dots C_{n}$ connected in series is given by

$C_{s} = \frac{1}{C _{1}} + \frac{1}{C _{2}} + \dots\dots .. + \frac{1}{C _{n}}$

$\frac{1}{C _{s}} = \frac{1}{C _{1}} + \dots\dots .. + \frac{1}{C _{n}}$

$C_{s} = C_{1} + C_{2} + \dots .. + C_{n}$

$C_{s} = C_{1} - C_{2} + \dots .. - C_{n}$

Correct answer is (b) $\frac{1}{C _{s}} = \frac{1}{C _{1}} + \dots\dots .. + \frac{1}{C _{n}}$

Q. The resultant capacitance of n condenser of capacitances C1​,C2​…Cn​ connected in series is given by

Cs​=C1​1​+C2​1​+……..+Cn​1​

Cs​1​=C1​1​+……..+Cn​1​

Cs​=C1​+C2​+…..+Cn​

Cs​=C1​−C2​+…..−Cn​