The respective speeds of five molecules are 2, 1.5, 1.6, 1.6 and 1.2 km s-1, the most probable speed in km s-1 will be

Question

The respective speeds of five molecules are 2, 1.5, 1.6, 1.6 and 1.2 km s-1, the most probable speed in km s-1 will be (A) 2 (B) 1.58 (C) 1.6 (D) 1.31

Tardigrade Admin · Accepted Answer

vmp = 0.816 vrms = 0.816 √(v21+v22+v32+v42+v52/N) =0.816 √((2)2+(1.5)2 +(1.6)2 +(1.6)2+(1.2)2/5) = 1.31 Km s-1

Q. The respective speeds of five molecules are 2, 1.5, 1.6, 1.6 and $1.2 km s^{- 1}$ , the most probable speed in $km s^{- 1}$ will be

2

1.58

1.6

1.31

$v_{m p} = 0.816 v_{r m s}$
$= 0.816 \frac{v _{1}^{2} + v _{2}^{2} + v _{3}^{2} + v _{4}^{2} + v _{5}^{2}}{N}$
$= 0.816 \frac{( 2 ) ^{2} + ( 1.5 ) ^{2} + ( 1.6 ) ^{2} + ( 1.6 ) ^{2} + ( 1.2 ) ^{2}}{5}$
$= 1.31 K m s^{- 1}$

Q. The respective speeds of five molecules are 2, 1.5, 1.6, 1.6 and 1.2kms−1, the most probable speed in kms−1 will be

2

1.58

1.6

1.31

vmp​=0.816vrms​ =0.816Nv12​+v22​+v32​+v42​+v52​​​ =0.8165(2)2+(1.5)2+(1.6)2+(1.6)2+(1.2)2​​ =1.31Kms−1

Q. The respective speeds of five molecules are 2, 1.5, 1.6, 1.6 and $1.2 km s^{- 1}$ , the most probable speed in $km s^{- 1}$ will be

$v_{m p} = 0.816 v_{r m s}$
$= 0.816 \frac{v _{1}^{2} + v _{2}^{2} + v _{3}^{2} + v _{4}^{2} + v _{5}^{2}}{N}$
$= 0.816 \frac{( 2 ) ^{2} + ( 1.5 ) ^{2} + ( 1.6 ) ^{2} + ( 1.6 ) ^{2} + ( 1.2 ) ^{2}}{5}$
$= 1.31 K m s^{- 1}$