Question

The resistivity of a $0.8M$ solution of an electrolyte is $5\times 10^{-3}\Omega cm$. Its molar conductivity is ____ $\times 10^4{\Omega }^{-1}c{m}^{2}mo{l}^{-1}$.

Answer 1

Answer: 25

${\Lambda }_m=\frac{\kappa \times 1000}{M}$
${\Lambda }_m=\frac{1}{\rho }\times \frac{1000}{M}$
$\frac{1}{5\times 10^{-3}}\times \frac{1000}{0.8}$
Ans. $25\times 10^4{\Omega }^{-1}c{m}^{-2}mo{l}^{-1}$