Q.
The resistance of the filament of a lamp increases with the increase in temperature. A lamp rated 100 W and 220 V is connected across 220 V power supply. If the voltage drops by 10%, then the power of the lamp will be
Let the resistance of the lamp filament be R.
Then, 100=(220)2/R.
When the voltage drops, expected power is P=(220×0.9)2/R′
Here, R′ will be less than R, because now the rise in temperature will be less.
Therefore, P is more than (220×0.9)2/R=81W.
But it will not be 90% of earlier value, because fall in temperature is small.