The resistance of conductivity cell containing 0.01 M KCl solution at 298 K is 1750 Ω. If the conductively of 0.01 M KCl solution at 298 K is 0.152 × 10-3 S cm -1, then the cell constant of the conductivity cell is × 10-3 cm -1.

Question

The resistance of conductivity cell containing 0.01 M KCl solution at 298 K is 1750 Ω. If the conductively of 0.01 M KCl solution at 298 K is 0.152 × 10-3 S cm -1, then the cell constant of the conductivity cell is × 10-3 cm -1. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

K =(1/ R ) × cell cons tan t 0.152 × 10-3=(1/1750) cell constant cell constant =266 × 10-3

Q. The resistance of conductivity cell containing $0.01 M K Cl$ solution at $298 K$ is $1750 Ω$ . If the conductively of $0.01 M K Cl$ solution at $298 K$ is $0.152 \times 1 0^{- 3} S c m^{- 1}$ , then the cell constant of the conductivity cell is _______ $\times 1 0^{- 3} c m^{- 1}$ .

$K = \frac{1}{R} \times$ cell cons $tan t$
$0.152 \times 1 0^{- 3} = \frac{1}{1750}$ cell constant
cell constant $= 266 \times 1 0^{- 3}$

Q. The resistance of conductivity cell containing 0.01MKCl solution at 298K is 1750Ω. If the conductively of 0.01MKCl solution at 298K is 0.152×10−3Scm−1, then the cell constant of the conductivity cell is _______×10−3cm−1.

K=R1​× cell cons tant 0.152×10−3=17501​ cell constant cell constant =266×10−3

Q. The resistance of conductivity cell containing $0.01 M K Cl$ solution at $298 K$ is $1750 Ω$ . If the conductively of $0.01 M K Cl$ solution at $298 K$ is $0.152 \times 1 0^{- 3} S c m^{- 1}$ , then the cell constant of the conductivity cell is _______ $\times 1 0^{- 3} c m^{- 1}$ .

$K = \frac{1}{R} \times$ cell cons $tan t$
$0.152 \times 1 0^{- 3} = \frac{1}{1750}$ cell constant
cell constant $= 266 \times 1 0^{- 3}$