1. Tardigrade
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  3. Chemistry
  4. The resistance of conductivity cell containing 0.01 M KCl solution at 298 K is 1750 Ω. If the conductively of 0.01 M KCl solution at 298 K is 0.152 × 10-3 S cm -1, then the cell constant of the conductivity cell is × 10-3 cm -1.

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Q. The resistance of conductivity cell containing $0.01 \,M \,KCl$ solution at $298\, K$ is $1750\, \Omega$. If the conductively of $0.01 \,M\, KCl$ solution at $298 \,K$ is $0.152 \times 10^{-3} S\, cm ^{-1}$, then the cell constant of the conductivity cell is _______$\times 10^{-3} \,cm ^{-1}$.

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Solution:

$K =\frac{1}{ R } \times$ cell cons $\tan t$
$0.152 \times 10^{-3}=\frac{1}{1750}$ cell constant
cell constant $=266 \times 10^{-3}$