The resistance of a N/10 KCl solution is 245 Ω. Calculate the equivalent conductance of the solution if the electrodes in the cell are 4 cm apart and each having an area of 7.0 sq. cm.

Question

The resistance of a N/10 KCl solution is 245 Ω. Calculate the equivalent conductance of the solution if the electrodes in the cell are 4 cm apart and each having an area of 7.0 sq. cm. (A) 23.32 S cm2 eq-1 (B) 23.23 S m2 eq-1 (C) 2.332 S cm2 eq-1 (D) None of these

Tardigrade Admin · Accepted Answer

245=(1/∧eq)×(4/7)×(1000/0.1) ⇒ ∧eq= 23.32 S cm2 eq-1

Q. The resistance of a $N /10 K Cl$ solution is $245Ω$ . Calculate the equivalent conductance of the solution if the electrodes in the cell are $4 c m$ apart and each having an area of $7.0 s q . c m .$

$23.32 S c m^{2} e q^{- 1}$

$23.23 S m^{2} e q^{- 1}$

$2.332 S c m^{2} e q^{- 1}$

None of these

$245 = \frac{1}{\land _{e q}} \times \frac{4}{7} \times \frac{1000}{0.1} \Rightarrow \land_{e q} = 23.32 S c m^{2} e q^{- 1}$

Q. The resistance of a N/10KCl solution is 245Ω. Calculate the equivalent conductance of the solution if the electrodes in the cell are 4cm apart and each having an area of 7.0sq.cm.

23.32Scm2eq−1

23.23Sm2eq−1

2.332Scm2eq−1