Question

The resistance of a $N/10 KCl$ solution is $245 \Omega$. Calculate the equivalent conductance of the solution if the electrodes in the cell are $4 \,cm$ apart and each having an area of $7.0\, sq.\, cm.$

• A. $23.32\, S\, cm^{2}\, eq^{-1}$
• B. $23.23\, S\, m^{2} \,eq^{-1}$
• C. $2.332\, S\, cm^{2}\, eq^{-1}$
• D. None of these

Answer 1

Answer: (A)

$245=\frac{1}{\wedge_{eq}}\times\frac{4}{7}\times\frac{1000}{0.1} \Rightarrow \wedge_{eq}= 23.32 \,S \,cm^{2} eq^{-1}$