The resistance of a galvanometer is 50 ohm and the maximum current which can be passed through it is 0.002 A. What resistance must be connected to it in order to convert it into an ammeter of range 0 - 0.5 A ?

Question

The resistance of a galvanometer is 50 ohm and the maximum current which can be passed through it is 0.002 A. What resistance must be connected to it in order to convert it into an ammeter of range 0 - 0.5 A ? (A) 0.2 ohm (B) 0.002 ohm (C) 0.02 ohm (D) 0.5 ohm

Tardigrade Admin · Accepted Answer

S(0.5 - 0.002) = 50 × 0.002 S = (50 × 0.002/(0.5 - 0.002)) = (0.1/0.498) = 0.2

Q. The resistance of a galvanometer is $50 o hm$ and the maximum current which can be passed through it is $0.002 A$ . What resistance must be connected to it in order to convert it into an ammeter of range $0 - 0.5 A$ ?

0.2 ohm

0.002 ohm

0.02 ohm

0.5 ohm

$S (0.5 - 0.002) = 50 \times 0.002$
$S = \frac{50 \times 0.002}{( 0.5 - 0.002 )} = \frac{0.1}{0.498} = 0.2$

Q. The resistance of a galvanometer is 50ohm and the maximum current which can be passed through it is 0.002A. What resistance must be connected to it in order to convert it into an ammeter of range 0−0.5A ?