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  4. The resistance of a galvanometer is 50 ohm and the maximum current which can be passed through it is 0.002 A. What resistance must be connected to it in order to convert it into an ammeter of range 0 - 0.5 A ?

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Q. The resistance of a galvanometer is $50\, ohm$ and the maximum current which can be passed through it is $0.002\, A$. What resistance must be connected to it in order to convert it into an ammeter of range $0 - 0.5\, A$ ?

JEE MainJEE Main 2019Moving Charges and Magnetism

Solution:

$S(0.5 - 0.002) = 50 \times 0.002$
$S = \frac{50 \times 0.002}{(0.5 - 0.002)} = \frac{0.1}{0.498} = 0.2 $

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