The resistance of a galvanometer is 25 Ω , and it requires 50 μ A for full deflection. The value of the shunt resistance required to convert it into an ammeter of 5 A is

Question

The resistance of a galvanometer is 25 Ω , and it requires 50 μ A for full deflection. The value of the shunt resistance required to convert it into an ammeter of 5 A is (A)  2.5× 10-4Ω  (B)  1.25× 10-3Ω  (C)  0.05 Ω  (D)  2.5 Ω

Tardigrade Admin · Accepted Answer

S=(IgG/I-Ig)=(50× 10-6× 24/5-50× 10-6) =2.5× 10-4 Ω

Q. The resistance of a galvanometer is $25 Ω$ , and it requires $50 μ A$ for full deflection. The value of the shunt resistance required to convert it into an ammeter of 5 A is

$2.5 \times 10^{- 4} Ω$

$1.25 \times 10^{- 3} Ω$

$0.05 Ω$

$2.5 Ω$

$S = \frac{I _{g} G}{I - I _{g}} = \frac{50 \times 10 ^{- 6} \times 24}{5 - 50 \times 10 ^{- 6}}$ $= 2.5 \times 10^{- 4} Ω$

Q. The resistance of a galvanometer is 25Ω , and it requires 50μA for full deflection. The value of the shunt resistance required to convert it into an ammeter of 5 A is

2.5×10−4Ω

1.25×10−3Ω

0.05Ω

2.5Ω