The resistance of 1 N solution of acetic acid is 250 Ω, when measured in a cell of cell constant 1.15 cm -1. The equivalent conductance (in ohm-1 cm2 equiv-1) of 1 N acetic acid is

Question

The resistance of 1 N solution of acetic acid is 250 Ω, when measured in a cell of cell constant 1.15 cm -1. The equivalent conductance (in ohm-1 cm2 equiv-1) of 1 N acetic acid is (A) 4.6 (B) 9.2 (C) 18.4 (D) 0.023

Tardigrade Admin · Accepted Answer

Equivalent conductivity (∧eq) = (K × 1000/C) Conductivity (K) = (cell constant/resistance) = (1.15/250) S cm-1 ∴ ∧eq = (1.15 × 1000/250 × 1) ∧eq = 4.6 ohm-1 cm2 equiv-1

Q. The resistance of 1 N solution of acetic acid is 250 $Ω$ , when measured in a cell of cell constant $1.15 c m^{- 1}$ . The equivalent conductance (in $o h m^{- 1} c m^{2} e q u i v^{- 1})$ of 1 N acetic acid is

4.6

9.2

18.4

0.023

Equivalent conductivity $(\land_{e q}) = \frac{K \times 1000}{C}$
$C o n d u c t i v i t y (K) = \frac{ce ll co n s t an t}{res i s t an ce}$
$= \frac{1.15}{250} S c m^{- 1}$
$∴ \land_{e q} = \frac{1.15 \times 1000}{250 \times 1}$
$\land_{e q} = 4.6 o h m^{- 1} c m^{2} e q u i v^{- 1}$

Q. The resistance of 1 N solution of acetic acid is 250 Ω, when measured in a cell of cell constant 1.15cm−1. The equivalent conductance (in ohm−1cm2equiv−1)of 1 N acetic acid is

4.6

9.2

18.4

0.023

Equivalent conductivity (∧eq​)=CK×1000​ Conductivity(K)=resistancecellconstant​ =2501.15​Scm−1 ∴∧eq​=250×11.15×1000​ ∧eq​=4.6ohm−1cm2equiv−1

Q. The resistance of 1 N solution of acetic acid is 250 $Ω$ , when measured in a cell of cell constant $1.15 c m^{- 1}$ . The equivalent conductance (in $o h m^{- 1} c m^{2} e q u i v^{- 1})$ of 1 N acetic acid is

Equivalent conductivity $(\land_{e q}) = \frac{K \times 1000}{C}$
$C o n d u c t i v i t y (K) = \frac{ce ll co n s t an t}{res i s t an ce}$
$= \frac{1.15}{250} S c m^{- 1}$
$∴ \land_{e q} = \frac{1.15 \times 1000}{250 \times 1}$
$\land_{e q} = 4.6 o h m^{- 1} c m^{2} e q u i v^{- 1}$