Question

The resistance of 1 N solution of acetic acid is 250 $\Omega$, when measured in a cell of cell constant $1.15 cm ^{-1}$. The equivalent conductance (in $ohm^{-1} cm^2 equiv^{-1}) $of 1 N acetic acid is

• A. 4.6
• B. 9.2
• C. 18.4
• D. 0.023

Answer 1

Answer: (A)

Equivalent conductivity $(\land_{eq}) = \frac{K \times 1000}{C}$
$ \, \, \, \, \, \, \, \, \, \, \, \, \, Conductivity (K) = \frac{cell \, constant}{resistance}$
$ \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, = \frac{1.15}{250} S \, cm^{-1}$
$ \therefore \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \land_{eq} = \frac{1.15 \times 1000}{250 \times 1}$
$ \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \land_{eq} = 4.6 \, ohm^{-1} \, cm^2 \, equiv^{-1}$