The resistance of 0.05 M CH3COOH solution is found to be 100 ohm. If the cell constant is 0.037 cm-1 the molar conductivity of the solution is

Question

The resistance of 0.05 M CH3COOH solution is found to be 100 ohm. If the cell constant is 0.037 cm-1 the molar conductivity of the solution is (A) 3.7 ohm-1 cm2 mol-1 (B) 74 ohm-1 cm2 mol-1 (C) 7.4 ohm-1 cm2 mol-1 (D) 37 ohm-1 cm2 mol-1

Tardigrade Admin · Accepted Answer

Electrolyte conductivity, k = (1/R)× cell constant = (1/100) × 0.037 = 3.7× 10-4 ohm-1 cm-1 ∴ Molar conductivity = (1000 × 3.7× 10-4/0.05) = 7.4 ohm-1 cm2 mol-1.

Q. The resistance of 0.05 $M C H_{3} COO H$ solution is found to be 100 ohm. If the cell constant is $0.037 c m^{- 1}$ the molar conductivity of the solution is

$3.7 o h m^{- 1} c m^{2} m o l^{- 1}$

$74 o h m^{- 1} c m^{2} m o l^{- 1}$

$7.4 o h m^{- 1} c m^{2} m o l^{- 1}$

$37 o h m^{- 1} c m^{2} m o l^{- 1}$

Electrolyte conductivity, $k = \frac{1}{R} \times$ cell constant
$= \frac{1}{100} \times 0.037 = 3.7 \times 1 0^{- 4} o h m^{- 1} c m^{- 1}$
$∴$ Molar conductivity $= \frac{1000 \times 3.7 \times 1 0 ^{- 4}}{0.05}$
$= 7.4 o h m^{- 1} c m^{2} m o l^{- 1}$ .

Q. The resistance of 0.05 MCH3​COOH solution is found to be 100 ohm. If the cell constant is 0.037cm−1 the molar conductivity of the solution is

3.7ohm−1cm2mol−1

74ohm−1cm2mol−1

7.4ohm−1cm2mol−1

37ohm−1cm2mol−1