The resistance of 0.0025 M solution of K 2 SO 4 is 326 ohm. The specific conductance of the solution, if cell constant is 4 .

Question

The resistance of 0.0025 M solution of K 2 SO 4 is 326 ohm. The specific conductance of the solution, if cell constant is 4 . (A) 4.997 × 10-4 (B) 5.997 × 10-7 (C) 6.997 × 10-4 (D) 1.20 × 10-2

Tardigrade Admin · Accepted Answer

K =(1/ρ)=(1/ R )(( l / a )) ⇒ (1/326) × 4=1.20 × 10-2

Q. The resistance of $0.0025 M$ solution of $K_{2} S O_{4}$ is $326 o hm$ . The specific conductance of the solution, if cell constant is $4.$

$4.997 \times 1 0^{- 4}$

$5.997 \times 1 0^{- 7}$

$6.997 \times 1 0^{- 4}$

$1.20 \times 1 0^{- 2}$

$K = \frac{1}{ρ} = \frac{1}{R} (\frac{l}{a})$
$\Rightarrow \frac{1}{326} \times 4 = 1.20 \times 1 0^{- 2}$

Q. The resistance of 0.0025M solution of K2​SO4​ is 326ohm. The specific conductance of the solution, if cell constant is 4.

4.997×10−4

5.997×10−7

6.997×10−4

1.20×10−2