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Q. The resistance of $0.0025 \,M$ solution of $K _{2} SO _{4}$ is $326 ohm$. The specific conductance of the solution, if cell constant is $4 .$

Electrochemistry

Solution:

$K =\frac{1}{\rho}=\frac{1}{ R }\left(\frac{ l }{ a }\right) $
$\Rightarrow \frac{1}{326} \times 4=1.20 \times 10^{-2}$