Q. The remainder when $(3 2^{32})^{32}$ is divided by $7$ , is

1837 227 Binomial Theorem Report Error

A

$2$

17%

B

$4$

50%

C

$6$

17%

D

$5$

17%

Solution:

$(3 2^{32})^{32} = 3 2^{1024} = (28 + 4)^{1024}$
$= 4 +$ a multiple of $28$ .
$= 4 +$ a multiple of $7$ .