The relative number of atoms of elements, 'X' and 'Y' in a compound is 0.25 and 0.5. The empirical formula of compound is

Question

The relative number of atoms of elements, 'X' and 'Y' in a compound is 0.25 and 0.5. The empirical formula of compound is (A) XY (B) X2Y (C) XY2 (D) X2Y2

Tardigrade Admin · Accepted Answer

Relative no. of moles of 'X' = (0.25/NA) = 0.25 and 'Y' = (0.5/NA) = 0.5 [ where,NA atom = 1 mole] Mole ratio of 'X' = 0.25/0.25=1 Mole ratio of 'Y' = 0.5/0.25 = 2 Empirical formula =XY2

Q. The relative number of atoms of elements, $^{'} X^{'}$ and $^{'} Y^{'}$ in a compound is $0.25$ and $0.5$ . The empirical formula of compound is

$X Y$

$X_{2} Y$

$X Y_{2}$

$X_{2} Y_{2}$

Relative no. of moles of $^{'} X^{'} = \frac{0.25}{N _{A}} = 0.25$ and
$^{'} Y^{'} = \frac{0.5}{N _{A}} = 0.5$ [ where, $N_{A}$ atom $= 1$ mole]
Mole ratio of $^{'} X^{'} = 0.25/0.25 = 1$
Mole ratio of $^{'} Y^{'} = 0.5/0.25 = 2$
Empirical formula $= X Y_{2}$

Q. The relative number of atoms of elements, ′X′ and ′Y′ in a compound is 0.25 and 0.5. The empirical formula of compound is

XY

X2​Y

XY2​

X2​Y2​