The relative humidity of air is text80 % at text27 texto textC text. .If the aqueous tension at the same temperature is text27 textmm of textHg text. The partial pressure of water vapour in the air will be (in textmm of textHg ).

Question

The relative humidity of air is text80 % at text27 texto textC text. .If the aqueous tension at the same temperature is text27 textmm of textHg text. The partial pressure of water vapour in the air will be (in textmm of textHg ). (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Relative humidity =(P a r t i a l p r e s s u r e/V a p o u r p r e s s u r e)× 100 ⇒ (P a r t i a l p r e s s u r e/27)× 100=80 ⇒ Partial pressure=(80 × 27/100) ∴ Partial pressure=21.6 mm of Hg

Q. The relative humidity of air is $80%$ at $27^{o} C .$ .If the aqueous tension at the same temperature is $27 mm$ of $Hg .$ The partial pressure of water vapour in the air will be (in $mm$ of $Hg$ ).

Relative humidity $= \frac{P a r t ia l p ress u re}{Va p o u r p ress u re} \times 100$

$\Rightarrow \frac{P a r t ia l p ress u re}{27} \times 100 = 80$

$\Rightarrow P a r t ia l p ress u re = \frac{80 \times 27}{100}$

$∴ P a r t ia l p ress u re = 21.6 mm$ of Hg

Q. The relative humidity of air is 80% at 27oC. .If the aqueous tension at the same temperature is 27mm of Hg. The partial pressure of water vapour in the air will be (in mm of Hg ).

Relative humidity =VapourpressurePartialpressure​×100 ⇒27Partialpressure​×100=80 ⇒Partialpressure=10080×27​ ∴Partialpressure=21.6mm of Hg

Q. The relative humidity of air is $80%$ at $27^{o} C .$ .If the aqueous tension at the same temperature is $27 mm$ of $Hg .$ The partial pressure of water vapour in the air will be (in $mm$ of $Hg$ ).

Relative humidity $= \frac{P a r t ia l p ress u re}{Va p o u r p ress u re} \times 100$

$\Rightarrow \frac{P a r t ia l p ress u re}{27} \times 100 = 80$

$\Rightarrow P a r t ia l p ress u re = \frac{80 \times 27}{100}$

$∴ P a r t ia l p ress u re = 21.6 mm$ of Hg