The relationship between energy E, of the radiation with a wavelength 8000 mathringA and the energy of the radiation with a wavelength 16000 mathringA is

Question

The relationship between energy E, of the radiation with a wavelength 8000 mathringA and the energy of the radiation with a wavelength 16000 mathringA is (A) E1=6 E2 (B) E1=2 E2 (C) E1=4 E2 (D) E1=1 / 2 E2

Tardigrade Admin · Accepted Answer

We know, E propto (1/λ) (E1/E2)=(λ2/λ1)=(16000/8000) ⇒ E1=2 E2

Q. The relationship between energy $E$ , of the radiation with a wavelength $8000 \overset{˚}{A}$ and the energy of the radiation with a wavelength $16000 \overset{˚}{A}$ is

$E_{1} = 6 E_{2}$

$E_{1} = 2 E_{2}$

$E_{1} = 4 E_{2}$

$E_{1} = 1/2 E_{2}$

We know, $E \propto \frac{1}{λ}$

$\frac{E _{1}}{E _{2}} = \frac{λ _{2}}{λ _{1}} = \frac{16000}{8000}$

$\Rightarrow E_{1} = 2 E_{2}$

Q. The relationship between energy E, of the radiation with a wavelength 8000A˚ and the energy of the radiation with a wavelength 16000A˚ is

E1​=6E2​

E1​=2E2​

E1​=4E2​

E1​=1/2E2​