Question

The relationship between energy $E$, of the radiation with a wavelength $8000 \,\mathring{A}$ and the energy of the radiation with a wavelength $16000 \,\mathring{A}$ is

• A. $E_{1}=6 E_{2}$
• B. $E_{1}=2 E_{2}$
• C. $E_{1}=4 E_{2}$
• D. $E_{1}=1 / 2 E_{2}$

Answer 1

Answer: (B)

We know, $E \propto \frac{1}{\lambda}$

$\frac{E_{1}}{E_{2}}=\frac{\lambda_{2}}{\lambda_{1}}=\frac{16000}{8000}$

$\Rightarrow E_{1}=2 E_{2}$