Let, A={1,2,3,4,5,6}
The relation R is defined on set A is R={(a,b):b=a+1}.
Therefore, R={(1,2),(2,3),(3,4),(4,5),(5,6)}
Now, 6∈A but (6,6)∈/R.
Therefore, R is not reflexive.
It can be observed that (1,2)∈R but (2,1)∈/R.
Therefore, R is not symmetric.
Now, (1,2),(2,3)∈R but (1,3)∈/R.
Therefore, R is not transitive.
Hence, R is neither reflexive nor symmetric nor transitive.