Q.
The relation R={(1, 1), (2, 2)(3, 3), (1, 2), (2, 3), (1, 3)} on set A={1, 2, 3} is
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Relations and Functions - Part 2
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Solution:
Reflexive :(1, 1), (2, 2), (3, 3)∈R, R is reflexive Symmetric : (1, 2)∈R but (2, 1)∈/R, R is not symmetric. Transitive : (1, 2)∈R and (2, 3)∈R ⇒(1, 3)∈R, R is transitive.