The relation between p and T during the adiabatic process with a monoatomic gas is pTn= constant. What is the value of n = ?

Question

The relation between p and T during the adiabatic process with a monoatomic gas is pTn= constant. What is the value of n = ? (A) (5/2) (B) -(5/2) (C) (3/2) (D) -(3/2)

Tardigrade Admin · Accepted Answer

pV &gamma; =K and pV = RT Hence p ( (Rt/p) )&gamma;=K or p1-&gamma; T&gamma;=K' Or (&gamma;/pT1-&gamma;) = K' For monoatomic gas &gamma; = 5/3

Q. The relation between p and T during the adiabatic process with a monoatomic gas is $p T^{n}$ = constant. What is the value of n = ?

$\frac{5}{2}$

$- \frac{5}{2}$

$\frac{3}{2}$

$- \frac{3}{2}$

$p V γ = K an d p V = RT$ $He n ce p (\frac{Rt}{p})^{γ} = K or p^{1 - γ} T^{γ} = K^{'} O r \frac{γ}{p T ^{1 - γ}} = K^{'}$ For monoatomic gas $γ$ = 5/3

Q. The relation between p and T during the adiabatic process with a monoatomic gas is pTn= constant. What is the value of n = ?

25​

−25​

23​

−23​