The region between the parallel plates of a capacitor is filled with parallel layers of air and paper (of dielectric constant 4). The space between the plates is 1 mm and the thickness of paper is 0.75 mm. The ratio of the voltages across air and paper is

Question

The region between the parallel plates of a capacitor is filled with parallel layers of air and paper (of dielectric constant 4). The space between the plates is 1 mm and the thickness of paper is 0.75 mm. The ratio of the voltages across air and paper is (A)  (1/2)  (B)  (3/4)  (C)  (4/3)  (D)  (1/3)

Tardigrade Admin · Accepted Answer

Here, d = 1 mm, t = 0.75 mm The given capacitor is equivalent to a two capacitors are connected in series. As in series charge on each capacitor is same, ∴ QA = QP where the subscripts A and P refer air and paper respectively, Thus, CA VA = CP VP (VA/VP) = (CP/CA) = ((e0KA/t)/(e0A)(d-t)) = (K(d-t)/t) = (4(0.25 mm)/0.75 mm) = (4/3)

Q. The region between the parallel plates of a capacitor is filled with parallel layers of air and paper (of dielectric constant $4$ ). The space between the plates is $1 mm$ and the thickness of paper is $0.75 mm$ . The ratio of the voltages across air and paper is

$\frac{1}{2}$

$\frac{3}{4}$

$\frac{4}{3}$

$\frac{1}{3}$

Q. The region between the parallel plates of a capacitor is filled with parallel layers of air and paper (of dielectric constant 4). The space between the plates is 1mm and the thickness of paper is 0.75mm. The ratio of the voltages across air and paper is

21​

43​

34​

31​

Q. The region between the parallel plates of a capacitor is filled with parallel layers of air and paper (of dielectric constant $4$ ). The space between the plates is $1 mm$ and the thickness of paper is $0.75 mm$ . The ratio of the voltages across air and paper is

$\frac{1}{2}$

$\frac{3}{4}$

$\frac{4}{3}$

$\frac{1}{3}$