The reduction potential of hydrogen electrode when placed in a buffer solution is found to be -0.413 V. The pH of the buffer is

Question

The reduction potential of hydrogen electrode when placed in a buffer solution is found to be -0.413 V. The pH of the buffer is (A) 10 (B) 4 (C) 7 (D) 12

Tardigrade Admin · Accepted Answer

-0.413 =0-0.059 log (1/[H+]) or (0.414/1.159)=-log H+ = PH or PH = 7

Q. The reduction potential of hydrogen electrode when placed in a buffer solution is found to be $- 0.413 V$ . The pH of the buffer is

$10$

$4$

$7$

$12$

$- 0.413 = 0 - 0.059 l o g \frac{1}{[ H ^{+} ]}$
or $\frac{0.414}{1.159} = - l o g H^{+} = P H or P H = 7$

Q. The reduction potential of hydrogen electrode when placed in a buffer solution is found to be −0.413V. The pH of the buffer is

10

4

7

12

−0.413=0−0.059log[H+]1​ or 1.1590.414​=−logH+=PHorPH=7

Q. The reduction potential of hydrogen electrode when placed in a buffer solution is found to be $- 0.413 V$ . The pH of the buffer is

$10$

$4$

$7$

$12$

$- 0.413 = 0 - 0.059 l o g \frac{1}{[ H ^{+} ]}$
or $\frac{0.414}{1.159} = - l o g H^{+} = P H or P H = 7$