The reduction potential of a half-cell consisting of a Pt electrode immersed in 1.5 M Fe2+ and 0.015 M Fe3+ solution at 25°C is (EoFe3+/Fe2+ = 0.770 V)is

Question

The reduction potential of a half-cell consisting of a Pt electrode immersed in 1.5 M Fe2+ and 0.015 M Fe3+ solution at 25°C is (EoFe3+/Fe2+ = 0.770 V)is (A) 0.652 V (B) 0.88 V (C) 0.710 V (D) 0.850 V

Tardigrade Admin · Accepted Answer

Ecell=0.77 -(0.059/1)log (1.5/0.015 )=0.652 V

Q. The reduction potential of a half-cell consisting of a Pt electrode immersed in $1.5$ M $F e^{2 +}$ and $0.015$ M $F e^{3 +}$ solution at $25° C$ is $(E_{F e^{3 +} / F e^{2 +} = 0.770 V)}^{o}$ is

$0.652$ V

$0.88$ V

$0.710$ V

$0.850$ V

$E_{ce ll} = 0.77 - \frac{0.059}{1} l o g \frac{1.5}{0.015} = 0.652 V$

Q. The reduction potential of a half-cell consisting of a Pt electrode immersed in 1.5 M Fe2+ and 0.015 M Fe3+ solution at 25°C is (EFe3+/Fe2+=0.770V)o​is

0.652 V

0.88 V

0.710 V

0.850 V