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  4. The reduction potential of a half-cell consisting of a Pt electrode immersed in 1.5 M Fe2+ and 0.015 M Fe3+ solution at 25°C is (EoFe3+/Fe2+ = 0.770 V)is

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Q. The reduction potential of a half-cell consisting of a Pt electrode immersed in $1.5$ M $Fe^{2+}$ and $0.015$ M $Fe^{3+}$ solution at $25°C$ is $(E^{o}_{Fe^{3+}/Fe^{2+} = 0.770\, V)}$is

Electrochemistry

Solution:

$E_{cell}=0.77 -\frac{0.059}{1}log \frac{1.5}{0.015 }=0.652 \,V$