The reduction potential (E0., in .V ) of MnO 4-( aq ) / Mn ( s ) is [. Given: .E( MnO 4( aq ) / MnO 2( s ))0=1.68 V ; E( MnO 2( s )/ Mn 2+( aq ))0=1.21 V ; E( Mn 2( aq ) / Mn ( s ))0=-1.03 V ]

Question

The reduction potential (E0., in .V ) of MnO 4-( aq ) / Mn ( s ) is [. Given: .E( MnO 4( aq ) / MnO 2( s ))0=1.68 V ; E( MnO 2( s )/ Mn 2+( aq ))0=1.21 V ; E( Mn 2( aq ) / Mn ( s ))0=-1.03 V ] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/4faa2d796768bc4b4013e99bdaefd78f-.png" /> For the required reaction Δ G °=Δ G °+Δ G 2°+Δ G ° ⇒ 7 × E =1.68 × 3+1.21 × 2+(-1.03) × 2 E =(5.4/7)=0.7714

Q. The reduction potential $(E^{0}$ , in $V)$ of $M n O_{4}^{-} (a q) / M n (s)$ is ___
$[$ Given : $E_{(M n O_{4} (a q) / M n O_{2} (s))}^{0} = 1.68 V; E_{(M n O_{2} (s) / M n^{2 +} (a q))}^{0} = 1.21 V; E_{(M n^{2} (a q) / M n (s))}^{0} = - 1.03 V]$

For the required reaction $Δ G^{\circ} = Δ G^{\circ} + Δ G_{2}^{\circ} + Δ G^{\circ}$
$\Rightarrow 7 \times E = 1.68 \times 3 + 1.21 \times 2 + (- 1.03) \times 2$
$E = \frac{5.4}{7} = 0.7714$

Q. The reduction potential (E0, in V) of MnO4−​(aq)/Mn(s) is ___ [ Given : E(MnO4​(aq)/MnO2​(s))0​=1.68V;E(MnO2​(s)/Mn2+(aq))0​=1.21V;E(Mn2(aq)/Mn(s))0​=−1.03V]

For the required reaction ΔG∘=ΔG∘+ΔG2∘​+ΔG∘ ⇒7×E=1.68×3+1.21×2+(−1.03)×2 E=75.4​=0.7714

Q. The reduction potential $(E^{0}$ , in $V)$ of $M n O_{4}^{-} (a q) / M n (s)$ is ___
$[$ Given : $E_{(M n O_{4} (a q) / M n O_{2} (s))}^{0} = 1.68 V; E_{(M n O_{2} (s) / M n^{2 +} (a q))}^{0} = 1.21 V; E_{(M n^{2} (a q) / M n (s))}^{0} = - 1.03 V]$

For the required reaction $Δ G^{\circ} = Δ G^{\circ} + Δ G_{2}^{\circ} + Δ G^{\circ}$
$\Rightarrow 7 \times E = 1.68 \times 3 + 1.21 \times 2 + (- 1.03) \times 2$
$E = \frac{5.4}{7} = 0.7714$