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Question
Mathematics
The reals x and y satisfy log 8 x+ log 4(y2)=5 and log 8 y+ log 4(x2)=7 then the value of x y is
Q. The reals
x
and y satisfy
lo
g
8
x
+
lo
g
4
(
y
2
)
=
5
and
lo
g
8
y
+
lo
g
4
(
x
2
)
=
7
then the value of
x
y
is
286
104
Continuity and Differentiability
Report Error
A
1024
B
512
C
256
D
81
Solution:
equation(1)
⇒
3
1
lo
g
2
x
+
lo
g
2
y
=
5......
(
3
)
and
equation(2)
⇒
3
1
lo
g
2
y
+
lo
g
2
x
=
7
.....(4)
(
3
)
+
(
4
)
⇒
3
1
lo
g
2
(
x
y
)
+
lo
g
2
(
x
y
)
=
12
⇒
3
4
lo
g
2
(
x
y
)
=
12
lo
g
2
(
x
y
)
=
9
⇒
x
y
=
2
9
=
512