The real value of a for which the value of m satisfying the equation (a2-1) m2-(2 a-3) m+a=0 gives the slope of a line parallel to the y-axis is

Question

The real value of a for which the value of m satisfying the equation (a2-1) m2-(2 a-3) m+a=0 gives the slope of a line parallel to the y-axis is (A) 3 / 2 (B) 0 (C) 1 (D) ± 1

Tardigrade Admin · Accepted Answer

A line parallel to the y-axis has slope ∞. Therefore, ( a 2-1) m 2-(2 a -3) m + a =0 must have one infinite root. So, a2-1=0 since both roots cannot be ∞ for then a2-1 =0 and 2 a -3 ≠ 0 are to hold for the same a.

Q. The real value of a for which the value of $m$ satisfying the equation $(a^{2} - 1) m^{2} - (2 a - 3) m + a = 0$ gives the slope of a line parallel to the $y$ -axis is

$3/2$

0

1

$\pm 1$

A line parallel to the $y$ -axis has slope $\infty$ .
Therefore, $(a^{2} - 1) m^{2} - (2 a - 3) m + a = 0$ must have one infinite root.
So, $a^{2} - 1 = 0$ since both roots cannot be $\infty$ for then $a^{2} - 1$ $= 0$ and $2 a - 3 \neq = 0$ are to hold for the same $a$ .

Q. The real value of a for which the value of m satisfying the equation (a2−1)m2−(2a−3)m+a=0 gives the slope of a line parallel to the y-axis is

3/2

0

1

±1

A line parallel to the y-axis has slope ∞. Therefore, (a2−1)m2−(2a−3)m+a=0 must have one infinite root. So, a2−1=0 since both roots cannot be ∞ for then a2−1 =0 and 2a−3=0 are to hold for the same a.

Q. The real value of a for which the value of $m$ satisfying the equation $(a^{2} - 1) m^{2} - (2 a - 3) m + a = 0$ gives the slope of a line parallel to the $y$ -axis is

$3/2$

$\pm 1$

A line parallel to the $y$ -axis has slope $\infty$ .
Therefore, $(a^{2} - 1) m^{2} - (2 a - 3) m + a = 0$ must have one infinite root.
So, $a^{2} - 1 = 0$ since both roots cannot be $\infty$ for then $a^{2} - 1$ $= 0$ and $2 a - 3 \neq = 0$ are to hold for the same $a$ .