The readings shown in two spring balances S1 and S2 are 90 kg and 30 kg, respectively, and the lift is accelerating upwards with an acceleration of 10 m / s 2. If the mass is stationary with respect to the lift, then the mass (in kg ) of -the block will be

Question

The readings shown in two spring balances S1 and S2 are 90 kg and 30 kg, respectively, and the lift is accelerating upwards with an acceleration of 10 m / s 2. If the mass is stationary with respect to the lift, then the mass (in kg ) of -the block will be (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

T1-T2-m g-m a=0 T1-T2=m(g+a) 600=m(10+10) ⇒ m=30 kg

Q. The readings shown in two spring balances $S_{1}$ and $S_{2}$ are $90 k g$ and $30 k g$ , respectively, and the lift is accelerating upwards with an acceleration of $10 m / s^{2}$ . If the mass is stationary with respect to the lift, then the mass (in $k g$ ) of -the block will be

$T_{1} - T_{2} - m g - ma = 0$
$T_{1} - T_{2} = m (g + a)$
$600 = m (10 + 10)$
$\Rightarrow m = 30 k g$

Q. The readings shown in two spring balances S1​ and S2​ are 90kg and 30kg, respectively, and the lift is accelerating upwards with an acceleration of 10m/s2. If the mass is stationary with respect to the lift, then the mass (in kg ) of -the block will be

T1​−T2​−mg−ma=0 T1​−T2​=m(g+a) 600=m(10+10) ⇒m=30kg

Q. The readings shown in two spring balances $S_{1}$ and $S_{2}$ are $90 k g$ and $30 k g$ , respectively, and the lift is accelerating upwards with an acceleration of $10 m / s^{2}$ . If the mass is stationary with respect to the lift, then the mass (in $k g$ ) of -the block will be

$T_{1} - T_{2} - m g - ma = 0$
$T_{1} - T_{2} = m (g + a)$
$600 = m (10 + 10)$
$\Rightarrow m = 30 k g$